Date.difference >= 0.1.8
Purpose
Determine the difference between two dates
Syntax
Date.difference
(
Stringunit
Datestart
Dateend
BooleanstartOfUnit= false
);
Parameters
unit
start
end
startOfUnit
Return values
Number
Examples
Return the differences
var a = new Date("2015-08-26T14:39:05.745Z"),
b = new Date("2015-08-14T10:31:10.045Z");
// When no units is given, ms is used
Date.difference(a, b);>>> -1051675700
// You can also supply seconds
Date.difference('seconds', a, b);>>> -1051675.7
Date.difference('minutes', a, b);>>> -17527.928333333333
Date.difference('hours', a, b);>>> -292.1321388888889
Date.difference('days', a, b);>>> -12.172172453703704
Date.difference('weeks', a, b);>>> -1.738881779100529
Date.difference('months', a, b);>>> -0.40573908179012347
Date.difference('years', a, b);>>> -0.03334841768138001
Return the difference from the start of the unit
var a = new Date("2015-08-26T14:39:05.745Z"),
b = new Date("2015-08-14T10:31:10.045Z");
// Will be calculated between "2015-08-26T14:39:05.000Z" and "2015-08-14T10:31:10.000Z"
Date.difference('seconds', a, b, true);>>> -1051675
// Will be calculated between "2015-08-26T14:39:00.000Z" and "2015-08-14T10:31:00.000Z"
Date.difference('minutes', a, b, true);>>> -17528
// Will be calculated between "2015-08-26T14:00:00.000Z" and "2015-08-14T10:00:00.000Z"
Date.difference('hours', a, b, true);>>> -292
Date.difference('days', a, b, true);>>> -12
Date.difference('weeks', a, b, true);>>> -2
Date.difference('months', a, b, true);>>> 0
Date.difference('years', a, b, true);>>> 0
Calculate between date strings
Date.difference('hours', "2015-08-26T14:00:00.000Z", "2015-08-14T10:00:00.000Z");>>> -292
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